regex, repeating group

[Riccardo Galli]

On Fri, 30 May 2003 15:32:18 -0400, Steven Scott wrote:

> say I'm working with this:
>   str = """body body body
> -><-
> Meeting Info
> From:you
> Attendees:me
> Date:now
> ID:0"""
> 
> I have this regular expression to get the data after colons, which I'm using 
> in re.search:
> 
> regex = r'-><-\n.+?\n(?:.+?:(.*?)\n?){4}$'
> 
> my problem is that this (when I call .groups()) only returns the last datum, 
> ('0',).  if I make the outer group non-grouping I only get ('ID:0', 
> '0')....still not any of the other lines of data.

I've never mastered the usage of {}, but if you use
regex = r'(.+:(.+)?\n?)'
and then
re.findall(regex,str)
you'll get
[('From:you\n', 'you'), ('Attendees:me\n', 'me'), ('Date:now\n', 'now'),
('ID:0', '0')]

it's useful.

note: it's really a bad idea use 'str' as variable name, 'cause it's a
type name.

Ciao,
Riccardo

-- 
-=Riccardo Galli=-

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