Find function name in function

[Terry Reedy]

"Sean Ross" <frobozz_electric at hotmail.com> wrote in message
news:badusu$3fi$1 at driftwood.ccs.carleton.ca...
> Okay, here you go...This function will identify the called functions
name by
> it's proper name or by it's alias, however it's being called. It
grabs the
> frame where the function was called, gets the associated code object
and
> last instruction index, disassembles the code object, isolates the
> instruction, and slices out the function name. I don't know if this
is
> robust, dangerous, or whatever, but it does what you're asking for.

As I pointed out in my first response to the OP, functions do not
necessarily have a 'called-by' name.

# revised be removing blank lines so cut and paste works
def whoami2():
    "returns name of called calling function"
    import sys, dis
    # get frame where calling function is called
    frame = sys._getframe(2)
    # get code and next to last instruction from frame
    code = frame.f_code
    lasti = frame.f_lasti-3
    # redirect ouput of disassemble (stdout)
    oldout = sys.stdout
    sys.stdout = open('log','w')
    dis.disassemble(code, lasti)
    sys.stdout.close()
    # restore stdout
    sys.stdout = oldout
    fd = open('log')
    # retrieve current byte code line
    current = [line for line in fd.readlines() if
line.startswith('-->')][0]
    fd.close()
    # isolate function name
    funcname = current.split()[-1][1:-1]
    return funcname

def XXX():
    print whoami2()

>>> XXX()
XXX # verifies copy ok
>>> fl=[XXX]
>>> fl[0]()
Traceback (most recent call last):
  File "<stdin>", line 1, in ?
  File "<stdin>", line 2, in XXX
  File "<stdin>", line 18, in whoami2
IndexError: list index out of range

I suppose you could wrap that line in try:except: and return '' in
this case.  But the user had better be prepared for a null name.

Terry J. Reedy