passing **kwargs to a function

[Erik Max Francis]

Bob Roberts wrote:

> def a(*args, **kwargs):
>     print args,kwargs
>     b(kwargs)
	...
> I am trying to pass int b() the exact same keyword arguments that were
> passed into it.  As you can see, it does't arrive in ths same way.  I
> want the kwargs variable inside a() and b() to be exactly the same.
> How do I do that?

Inside a, kwargs is just a local variable that happens to be a
dictionary.  So when you call b(kwargs), you're just calling b with a
dictionary object as the first argument.  What you meant was:

	b(**kwargs)

-- 
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