handling errors
ataraxia2500
messageboardfan1 at yahoo.com
Wed Jun 4 20:38:15 EDT 2003
I got that little piece of code on a tutorial. I want to add an error
handling to the print_menu function so that if the user enter strings
instead of int the program doesn't crash but I couldn't make it. I tried to
add: "except ValueError:
print "That was not a number.""
at the end but it didn't do anything. any idea how I should use it?
thanx in advance
def print_menu():
print '1. Print Phone Numbers'
print '2. Add a Phone Number'
print '3. Remove a Phone Number'
print '4. Lookup a Phone Number'
print '5. Quit'
print
numbers = {}
menu_choice = 0
print_menu()
while menu_choice != 5:
menu_choice = input("Type in a number (1-5):")
if menu_choice == 1:
print "Telephone Numbers:"
for x in numbers.keys():
print "Name: ",x," \tNumber: ",numbers[x]
print
elif menu_choice == 2:
print "Add Name and Number"
name = raw_input("Name:")
phone = raw_input("Number:")
numbers[name] = phone
elif menu_choice == 3:
print "Remove Name and Number"
name = raw_input("Name:")
if numbers.has_key(name):
del numbers[name]
else:
print name," was not found"
elif menu_choice == 4:
print "Lookup Number"
name = raw_input("Name:")
if numbers.has_key(name):
print "The number is",numbers[name]
else:
print name," was not found"
elif menu_choice != 5:
print_menu()
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