TypeError: Value() takes at most 2 arguments (3 given)

[Max Barry]

Oops, there was a typo. You are right def foo() should be def foo(self).  I
am still getting the TypeError.  Any other suggestions.

Updated example:

 class someclass:
    def foo(self):
	self.test(somevbobject)

    def test(self, Result):
        Result.Value(1, 0)

This is the VB property that python calls:
Public Property Let Value(ByVal lngIndex As Long, ByVal sngNew As Single)
    ' Notice: presumed to be zero-based values
    msngValues(lngIndex + 1) = sngNew
End Property

Thanks,
max



-----Original Message-----
From: python-list-admin at python.org
[mailto:python-list-admin at python.org]On Behalf Of vincent wehren
Sent: Thursday, June 19, 2003 12:06 PM
To: python-list at python.org
Subject: Re: TypeError: Value() takes at most 2 arguments (3 given)


"Max Barry" <max at ford-consulting.com> schrieb im Newsbeitrag
news:mailman.1056044255.14205.python-list at python.org...
> I am having problems calling a VB6 let property from a class in python.  I
> get a TypeError: Value() takes at most 2 arguments (3 given).  I presume
the
> self is being passed as the 3rd argument.  Here is an example of the
class:
>
> class someclass:
>     def foo():
How's about:

   def foo(self):
       self.test(somevbobject)

Regards,
Vincent Wehren


> self.test(somevbobject)
>
>     def test(self, Result):
>         Result.Value(1, 0)
>
>
> This is the VB property that python calls:
> Public Property Let Value(ByVal lngIndex As Long, ByVal sngNew As Single)
>     ' Notice: presumed to be zero-based values
>     msngValues(lngIndex + 1) = sngNew
> End Property
>
> Does anybody know how to resolve this problem?
>
> Thanks in advance,
> Max
>
>
>
>
>


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