Variable Modifications in a class

[Bernard Yue]

Mehta, Anish wrote:

>  Thanks for the explaination.  That point is clear and also one thing 
> more is that when we have the same piece of code in c , and when we do 
> 'c = b' then copy constructor is invoked. So in c with the 
> same(likely) piece of code we have differnt output from python. I 
> would like to know is there any way with which i can write the code in 
> python for the C code like below.
> I am writing a program in python which is already written in C and in 
> that lot of instances are modifying the variables of the some 
> structure like this:
>
>
> typedef struct ab
> {
>       int a;
>       int b;
> }AB;
>
> main()
> {
>  AB b;
>  AB c;
>
>  b.a = 5;
>  b.b = 10;
>
>  c = b;
>
>  c.a = 30;
>  c.b = 40;
>
>  printf("AB values %d %d\n", b.a, b.b);
>  printf("New values %d %d\n", c.a, c.b);
> }
>
> The output is:
>
> AB values 5 10
> New values 30 40

use module copy.  Code as follows:

import copy

class AB:
  def __init__(self):
      self.a = None
      self.b = None

def func(ab):
  b = ab()
  # c = ab()

  b.a = 5
  b.b = 10

  c = copy.deepcopy(b)

  c.a = 30
  c.b = 40

  print b.a, b.b
  print c.a, c.b
  t = func(AB)


>
>> So let's run through your function line by line
>>
>> def func(ab):
>>    b = ab()
>>
>> This creates a new AB object, the first one.
>> It also creates the name "b", and binds it to the new AB object.
>>
>>    c = ab()
>>
>> This also creates a new (and different) AB object, the second one.
>> It also creates the name "c", and binds it to the second AB object.
>>
>>    b.a = 5
>>
>> Set the "a" member of the AB object *referred to* to by "b" to 5
>>
>>    b.b = 10
>>
>> Set the "b" member of the AB object *referred to* to by "b" to 10
>>
>>    c = b
>>
>> Make the name "c" refer to whatever "b" refers to
>> (in this case, the *first* AB object).
>> Note also that you now have no way of getting at the second AB 
>> object, since you have no reference to it. It has fallen into the
>> garbage heap, and will be recycled eventually.
>>
>>   c.a = 30
>>
>> Set the "a" member of the AB object referred to by c (i.e. the first AB
>> object) to 30
>>
>>   c.b = 40
>>
>> Set the "b" member of the AB object referred to by c (i.e. the first AB
>> object) to 40
>>
>> I think you will understand the behaviour better now.
>>
>> HTH,
>>
>>  
>>
>
>
>