properties + types, implementing meta-class desciptors elegantly?
Michele Simionato
mis6 at pitt.edu
Mon Jul 21 09:33:12 EDT 2003
"Mike C. Fletcher" <mcfletch at rogers.com> wrote in message news:<mailman.1058717611.28555.python-list at python.org>...
> Michele Simionato wrote:
>
> >"Mike C. Fletcher" <mcfletch at rogers.com> wrote in message news:<mailman.1058629890.30475.python-list at python.org>...
> ><snip>
> >
> >As others before me, I am not sure of what you are trying to do
> >and why you are doing so. I use descriptors in this way:
> >
> >class o(object):
> > class p( object ): # descriptor class
> > def __set__( self, client, value, *args, **named ):
> > print '__set__', self, client, value, args, named
> > self.v=value
> > def __get__(self,obj,cls):
> > return self.v
> > v = p()
> >
> You are aware that you have just created a class-attribute, rather than
> an instance attribute? The property/descriptor object exists within the
> class 'o' namespace, not the instance namespace. Try creating two
> instances of your o class and setting v on both of them. There is one
> 'p' instance "self" to which you are assigning/retrieving an attribute
> for all instances of o. Creating class variables is certainly a valid
> use for descriptors, but I'm not sure if that's really what you were
> trying to do.
I have just copied your code, I thought you wanted a class attribute.
It is is trivial to do the same for instance attributes:
class o(object):
class p( object ): # descriptor class
def __set__( self, client, value, *args, **named ):
print '__set__', self, client, value, args, named
self.value=value
def __get__(self,obj,cls):
return self.value
def __init__(self):
self.v = self.p()
I understand that you aware of this, but you don't like it. Still I
do not understand why do you feel it to be ugly and/or inelegant. It
seems to me quite idiomatic.
> What I'm looking for, in terms of your code, is a method/function which
> would do the proper thing instead of using "self.v=value", (or rather
> client.__dict__['v'] = value (i.e. store the value in the client
> dictionary)) for all of the major built-in types, such as
> object-instances, classes (and object-instances with slots would be
> nice). To the best of my knowledge, such a function does not exist
> within Python; for instances, simply doing instance.__dict__[ key ] =
> value is sufficient, but classes do not have a method exposed AFAIK
> which allows an equivalent setting of a value *without* triggering the
> descriptor machinery for the given key.
Yes, I understand you want to be able to set class dictionaries just
as object dictionaries, bypassing descriptors. Still, I am not sure
if this would be a good idea.
> I'm creating a slightly more involved pattern, by the way:
>
> class plugin( type ):
> someHelperClass = common.ClassByNameProperty(
> "someHelperClass", """Documentation for this meta-property""",
> defaultValue = "some.package.module.ClassName",
> setDefaultOnGet = 0,
> )
>
> class MyWorkingPlugIn( myBaseImplementation ):
> __metaclass__ = plugin
>
> instance = MyWorkingPlugIn()
>
> Where the properties of the plugin meta-class are providing all sorts of
> services for the MyWorkingPlugIn class, such as allowing it to find
> "someHelperClass" related to the plug-in system while allowing that
> property to be set manually if desired, or automatically calculating a
> global identifier if the plug-in doesn't currently have a global
> identifier. The value is primarily that the meta-class will use exactly
> the same mechanisms as the rest of the system, and so will be readily
> dealt with by the property-based meta-application system.
>
> There are certainly other ways to get around the particular problem (I
> have already done that), I'm looking for the *elegant* solution to the
> *general* case.
>
Elegance is in the eye of the beholder ;)
> Enjoy,
> Mike
>
> _______________________________________
> Mike C. Fletcher
> Designer, VR Plumber, Coder
> http://members.rogers.com/mcfletch/
Good luck with your project,
Michele
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