Idiomatic way of repeating items in a sequence.

[Jonathan Bober]

On Mon, 2003-06-30 at 10:53, Batista, Facundo wrote:

> Whitout a lambda and without a for:
> 
> def repeatitems(L, n):
> 	return [x for x in L*n]
> 
> CAUTION: the resulting list is not in the same order of your example:
> 
> >>> repeatitems(['a', 'b', 'c'], 3)
> ['a', 'b', 'c', 'a', 'b', 'c', 'a', 'b', 'c']

OUCH!!!
this code hurts so bad that i must respond...

L * n

is the same as 

[x for x in L * n]

except that the latter iterates through L * n applying the identity
transformation, and is much much slower.

keep things simple.