list_to_dict()

[Peter Abel]

maney at pobox.com wrote in message news:<b06v5g$auj$2 at wheel2.two14.net>...
> Skip Montanaro <skip at pobox.com> wrote:
> > 
> >    maney> def list_to_dict(aList, key_indexes, value_indexes):
> >           ...
> > 
> > In 2.3 (and somewhat earlier I believe), you can call the dict() type like
> > so:
> > 
> >    >>> dict([("one", 1), ("two", 2)])
> >    {'two': 2, 'one': 1}
> 
> Which is a little bit like, but not usefully since the key is neither
> always the first item nor necessarily a single item in the source
> records.
> 
> > You can, of course, smash your keys and values lists together using zip():
> 
> Oh yeah, I do that quite a bit, too (though not in the program that
> gave rise to dict_from_list).
> 
> > 
> >    >>> zip(("one", "two"), (1, 2))
> >    [('one', 1), ('two', 2)]
> 
> So for the current use I'd have something like
> 
> theDict = dict(zip([(r[1],r[2]) for r in aList],
>                    [(r[0],r[2],r[3]) for r in alist]))
> 
> Hmmmm.  I can't say it looks like an improvement over the simple loop
> to my eyes.  If anything it's buried the distinguishing features - the
> original list and the lists of indexes - under a slightly greater
> weight of scaffolding.
> 
> There's some food for thought about related uses here, though.  Thanks,
> Skip!

Sorry, when i didn't read the thread quite exactly,
but I think your basic problem is something like this, which can
be easily solved.
I'm using PYTHON 2.2.2:
>>> l1=['zero','one','two','three']
>>> l2=range(5)
>>> l1
['zero', 'one', 'two', 'three']
>>> l2
[0, 1, 2, 3, 4]
>>> di=dict(zip(l1,l2))
>>> di
{'zero': 0, 'three': 3, 'two': 2, 'one': 1}
>>> 

Regards
Peter