socket.accept()

[Andrew Bennetts]

On Tue, Feb 11, 2003 at 12:43:59AM +0100, marco wrote:
> very much simplified a function looks like this:
> 
> def run():
>   mysocket = socket.socket(blabla)
>   mysocket.bind(blabla)
>   mysocket.listen(1)
>   while 1:
>     newsocket, addr = mysocket.accept()
>     # and so on...
> 
> now this loop is in a thread which, once started, will
> never die. since a thread must (?) be killed at the
> end of the program i do have a problem, because the
> program just doesn't exit
> how can i stopp the .accept()?
> 
> any help would be appreciated

Two suggestions:

If a threading.Thread is "daemonic", the program can finish without you
needing to stop the thread.  Look at the "setDaemonic" method in the docs.

Secondly, if your server is even slightly complex, I strongly recommend
using a prewritten socket framework, rather than doing it yourself.  I
personally prefer Twisted <http://twistedmatrix.com/>, but SocketServer or
asyncore may also be sufficient for your needs.

-Andrew.