Unexpected behaviour from the 'in' operator

[sik0fewl]

Blair Hall wrote:
> I have just noticed that the 'in' operator for lists appears to
> use the __eq__ method of a class. This does not
> provide the behaviour I expected when implementing
> an ad hoc numeric class type.
> 
> Here is some code:
> 
> class A(object):
>     def __init__(self,x):
>         self.x = x
> 
>     def __eq__(self,other):
>         print 'eq'
>         return self.x == other
> #=============================
> if(__name__ == '__main__'):
>     print
>     x = A(1)
>     y = A(1)
>     lst = [x]
>     print y in lst        # prints 1
> 
> The 'y in lst' expression evaluates to true here, because
> both x and y are equal to the same value. However,
> x and y are not the same object!  It seems to me that
> the comparison should use something like the id() function
> instead of __eq__.
I don't know. It works the way I would've expected it to work. Because, 
like you said, x == y and x is in list, therefore y is in list.

--
Ryan