How to call script in interative status

[Fu Chen]

yes, i write the script like below

#######################################################
def main():
	import getopt
	try:
		opts, args = getopt.getopt(sys.argv[1:], "slc:d:e:")
	except getopt.error, why:
			print why
			print usage % (os.path.basename(sys.argv[0],))
			return

	bCallback = 0
	if args or not opts:
		print usage % (os.path.basename(sys.argv[0],))
		return
	for opt, val in opts:
		if opt=="-s":
			bCallback = 1
		if opt=="-l":
			ShowConnections()
		if opt=="-c":
			hras, rc = Connect(val, bCallback)
			if hras != None:
				print "hras: 0x%8lx, rc: 0x%04x" % ( hras, rc )
		if opt=="-d":
			Disconnect(val)
		if opt=="-e":
			EditEntry(val)

if __name__=='__main__':
	main()

######################################################

then in the command line >>>, how can i run it with args?
import script
script.main()
but where is the args to input?

I know i can press ctrl-R in pythonwin to invoke a dialog to enter the
args, but i hate it if i have to run it several times.

Steven Taschuk <staschuk at telusplanet.net> wrote in message news:<mailman.1046368237.24643.python-list at python.org>...
> Quoth Fu Chen:
> > Hi!
> > 
> > I use python under windows2k. 
> > Uptonow i only call script by 
> > python script.py arg1 arg2
> > 
> > My question is can we call a script under the interative status ( >>>
> > ) and how to do ? it seems possible to import a script and call its
> > function like script.func, but how to run the segment marked by name
> > == '__MAIN__' ?
> 
> Usually the best thing is to write the script like this:
> 
>     def do_something():
>         ...
>     if __name__ == '__main__':
>         do_something()
> 
> Then it can be run programmatically by importing it and calling
> do_something.
> 
> Alternatively, there's all the process management functions in the
> os module.