Function application optimization.

[Bengt Richter]

On 12 Dec 2003 10:47:50 +0100, Jacek Generowicz <jacek.generowicz at cern.ch> wrote:

>Given
>
>  fncs = [func1, func2, ..., funcN]
>  args = [arg1,  arg2,  ..., argN]
>
>How should one spell
>
>  results = map(lambda f,a: f(a), fncs, args)
>
>in order to get the result most quickly ?
>
>
>
>Unfortunately "apply" takes a tuple of arguments, and there is no
>"funcall"[*] in Python.
>
>
>[*] def funcall(fn, *args):
>        return fn(*args)
>

 >>> fncs = [lambda x,f='func_%s(%%s)'%i:f%x for i in xrange(4)]
 >>> args = 'zero one two three'.split()
 >>> map(lambda f,a: f(a), fncs, args)
 ['func_0(zero)', 'func_1(one)', 'func_2(two)', 'func_3(three)']

I'd probably try a list comprehension

 >>> [f(a) for f,a in zip(fncs,args)]
 ['func_0(zero)', 'func_1(one)', 'func_2(two)', 'func_3(three)']

Regards,
Bengt Richter