string.count issue (simple)

[Alex Martelli]

Halfdan Holger Knudsen wrote:

> ok first off: Has the string.count function been replaced in python 2.2
> (as compared to 1.5)?m And second:
> 
> I need this in relation to a stringsearch program
> assuming a text file has been loaded into allLines and word contains the
> string you're searching for I want to count all occurences of the search
> string the following should do it (but doesn't - please disregard any
> missing colons or such this has not been copy/pasted):
> 
> count = 0
> 
> for eachLine in allLines:
>     if eachLine.find(word) > -1:
>         count = count + eachLine.count(word, beg=0, end=len(eachLine)

Method count does not take keyword arguments.  Besides, the ones you're
specifiying are redundant, and the if's condition is double work.

>         print eachLine
> print count

I would recode this as:

count = 0
for eachLine in allLines:
    countOnLine = eachLine.count(word)
    if countOnLine:
        count = count + countOnLine
        print eachLIne
print count


> what am I missing - it only outputs the nubmer of lines (as if the count
> statement had been count = count + 1)

Hard to explain, since the code you're posting (with the keyword
arguments) can't possibly be the one you're running.


Alex