passing no arguments to a callback function question

[matthew]

Hi,

I'm pretty new to python and most of my stumblings get me somewhere but 
I'm stumped on this. Given the following code/exception how do I avoid 
the exception generated when notify_listeners is called?


     def __init__(self, file_to_process):
       	NC_Scanner.__init__(self, file_to_process, self.lexicon, 
self.event_types)
         self.add_listener('any', print_event, 'any')
         self.add_listener('position', print_params, args=None)


     def event_end(self, scanner):
         self.notify_listeners('any')
         self.notify_listeners(self.state_name) # initiates callbacks 
for   the particular event scanned in Plex
         self.begin('')

     def print_params():
     	print 'PARAMS: ', params

gives:-

   File "D:\Python22\Lib\site-packages\TeePee\notifier.py", line 39, in 
__call__
     return self.fn(*(self.args + args), **d)
TypeError: print_params() takes no arguments (1 given)

I hope this isn't too garbled. Thanks for the help. matthew.