hex and unsigned longs

[Igor V. Rafienko]

Hi,

The documentation for the built-in function hex() says that hex()
always returns an unsigned literal. However, on my 2.2.1 python, I get
the following results:

>>> hex( 1 )
'0x1'
>>> hex( 1L )
'0x1L'
>>> hex( -1 )
'0xffffffff'
>>> hex( -1L )
'-0x1L'
>>> 

The literal in the last case is obviously not unsigned. What am I
missing? (I.e. why are longs treated differently than ints by hex?)

TIA,





ivr
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