a python puzzle

[Michal Wallace]

On Thu, 26 Sep 2002, holger krekel wrote:

> OK.  something like 
> 
> def decrypt(yourstring):
>     dedict = {'F': 'S', 'I': 'C', 'H': 'I', 'a': 't', 'c': 'f', 'b': 'v', 'e': 'n',
>     'd': 'o', 'f': 's', 'i': 'c', 'h': 'i', 'k': 'p', 'j': 'h', 'm': 'l',
>     'l': 'j', 'o': 'm', 'q': 'u', 'p': 'w', 's': 'b', 'u': 'z', 't': 'd',
>     'w': 'y', 'v': 'x', 'y': 'e', 'x': 'a', 'z': 'g', 'g': 'k'}
>     return "".join([dedict.get(i,i) for i in yourstring])
> returns
...
>     It's time to test your brainpower! I will give
>     six months of free web hosting to the first person
>     to solve this cryptogram. Can you figure it out?


Hi Holger,

Yep, that's it! I figured it would be easy to solve -
especially given the python code, but I didn't expect a
solution THAT quick. Next time I'm using RSA!

> but i don't know if i need free webhosting :-)

Hahaha. Well, if you change your mind, just let me know. :)

Cheers,

- Michal   http://www.sabren.net/   sabren at manifestation.com 
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