comparing all values of a list to regex

[Delaney, Timothy]

> From: Alex Martelli [mailto:aleax at aleax.it]
> 
> num_matches = [ there.match(item) is not None for item in 
> alist ].count(1)
> 
> if num_matches == 0:
>     againanothernewlist.append(alist)
> elif num_matches == 1:
>     anothetnewlist.append(alist)
> elif num_matches == len(alist):
>     anewlist.append(alist)

I would actually prefer to do this another way.

match_all = []
match_one = []
match_some = []
match_none = []

# Expanded out for clarity - could be one line
matches = map(regexp.match, alist)
matches = filter(None, matches)
matches = len(matches)

# Find out which list to append to

match_list = match_all

if not matches:
    match_list = match_none
elif matches == 1:
    match_list = match_one
elif matches != len(alist):
    match_list = match_some

match_list.append(alist)

Note that I added an additional case - where more than one matched, but not
all.

Tim Delaney