a python puzzle

[holger krekel]

Michal Wallace wrote:
> On Thu, 26 Sep 2002, holger krekel wrote:
> 
> > OK.  something like 
> > 
> > def decrypt(yourstring):
> >     dedict = {'F': 'S', 'I': 'C', 'H': 'I', 'a': 't', 'c': 'f', 'b': 'v', 'e': 'n',
> >     'd': 'o', 'f': 's', 'i': 'c', 'h': 'i', 'k': 'p', 'j': 'h', 'm': 'l',
> >     'l': 'j', 'o': 'm', 'q': 'u', 'p': 'w', 's': 'b', 'u': 'z', 't': 'd',
> >     'w': 'y', 'v': 'x', 'y': 'e', 'x': 'a', 'z': 'g', 'g': 'k'}
> >     return "".join([dedict.get(i,i) for i in yourstring])
> > returns
> ...
> >     It's time to test your brainpower! I will give
> >     six months of free web hosting to the first person
> >     to solve this cryptogram. Can you figure it out?
> 
> 
> Hi Holger,
> 
> Yep, that's it! I figured it would be easy to solve -
> especially given the python code, but I didn't expect a
> solution THAT quick. Next time I'm using RSA!

No problem :-)

Just letting out the python code would make it a bit harder.
One might even have to start to seriously program ...

> > but i don't know if i need free webhosting :-)
> 
> Hahaha. Well, if you change your mind, just let me know. :)

cheers,

    holger