__call__ question

[Michael Hudson]

Rick <r.l.richardson at verizon.net> writes:

> If I generate a call method inside a class class with def
> __call__(self, arg1): ...
> everything is hunkey dorey.  However if I generate the class then
> later try to add the __call__ function with setattribute or by create
> a function that behaves like call should and then assigning it to
> myobj.__class__ I can't call the instance of the class like a callable
> object. It states that that instance is not a callable object. I can
> however:
> 
> myobj.__call__(myobj, arg1)
> and it works. Anyone know what I have to do to make an object callable
> at runtime?

Works for me:

>>> class C:
...  pass
... 
>>> c = C()
>>> 
>>> def call(self, x):
...  print self, x
... 
>>> C.__call__ = call
>>> 
>>> c(2)
<__main__.C instance at 0x81929e4> 2

Works the same with new-style classes too.  What goes wrong for you?

Cheers,
M.

-- 
  I'd certainly be shocked to discover a consensus.  ;-)
                                      -- Aahz Maruch, comp.lang.python