xslt in PyXml 0.8.1 doesn't work?
Jane Austine
janeaustine50 at hotmail.com
Tue Oct 1 08:53:13 EDT 2002
Sorry if I'm knocking on the wrong door.
xslt package in PyXml 0.8.1 doesn't work with Python 2.2.
>>> from xml.xslt.Processor import Processor
>>> p=Processor()
>>> p.appendStylesheetUri('test.xsl')
...
File "C:\Python22\lib\site-packages\_xmlplus\xslt\Processor.py",
line 95, in appendStylesheetUri
sty = self._styReader.fromUri(styleSheetUri, baseUri)
File "C:\Python22\lib\site-packages\_xmlplus\xslt\StylesheetReader.py",
line 298, in fromUri
ownerDoc, stripElements)
File "C:\Python22\lib\site-packages\_xmlplus\xslt\minisupport.py",
line 58, in fromUri
return self.fromStream(stream, baseUri, ownerDoc, stripElements)
File "C:\Python22\lib\site-packages\_xmlplus\xslt\StylesheetReader.py",
line 305, in fromStream
self.initParser()
File "C:\Python22\lib\site-packages\_xmlplus\xslt\StylesheetReader.py",
line 355, in initParser
self.parser.ExternalEntityRefHandler = self.handler.entityRef
AttributeError: StylesheetReader instance has no attribute 'entityRef'
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