xslt in PyXml 0.8.1 doesn't work?

Jane Austine janeaustine50 at hotmail.com
Tue Oct 1 08:53:13 EDT 2002


Sorry if I'm knocking on the wrong door.

xslt package in PyXml 0.8.1 doesn't work with Python 2.2.

>>> from xml.xslt.Processor import Processor
>>> p=Processor()
>>> p.appendStylesheetUri('test.xsl')
  ...
  File "C:\Python22\lib\site-packages\_xmlplus\xslt\Processor.py",
line 95, in appendStylesheetUri
    sty = self._styReader.fromUri(styleSheetUri, baseUri)
  File "C:\Python22\lib\site-packages\_xmlplus\xslt\StylesheetReader.py",
line 298, in fromUri
    ownerDoc, stripElements)
  File "C:\Python22\lib\site-packages\_xmlplus\xslt\minisupport.py",
line 58, in fromUri
    return self.fromStream(stream, baseUri, ownerDoc, stripElements)
  File "C:\Python22\lib\site-packages\_xmlplus\xslt\StylesheetReader.py",
line 305, in fromStream
    self.initParser()
  File "C:\Python22\lib\site-packages\_xmlplus\xslt\StylesheetReader.py",
line 355, in initParser
    self.parser.ExternalEntityRefHandler = self.handler.entityRef
AttributeError: StylesheetReader instance has no attribute 'entityRef'



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