Getting the line where an exception is raised

[JB]

Steve Holden wrote:

Thank you vey much, but your suggestion does not really 
help. Here is my code:

    try:
      exec tmp in user_name_space
    except:
        txt = str(sys.exc_info()[1])
        i = traceback.tb_lineno(sys.exc_info()[2])
        print '*',txt,'*',i,'*'
        mw.widget.text.eingabe.setCursorPosition(i,0)
        mw.widget.text.ausgabe.setReadOnly(0)
        mw.widget.text.ausgabe.setText('<font color=red> 
'+txt+'</font>')
        mw.widget.text.ausgabe.setReadOnly(1)

(I use PyQt.)
Now I always receive the line number 41 from 
traceback.tb_lineno(sys.exc_info()[2]), 
as the exec statement happens to be in the 41th line of my 
code. But the error message say somthig like "syntax error 
in (line 11)" and /this/ line number is ok. (tmp contains 
several lines of code.)

-- 
J.... B....


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