Problem with list assignment

[OKB (not okblacke)]

Jesse Lawrence wrote:

>    i = 0;
>    for r in row:
>       header[i] = r[0]
>       i = i + 1
>    return header
> 
> Now, when I just do a print r[0] in the for loop, I'm
> getting exactly what I want, it's just that when I try
> to assign it to header, that I get a "list assignment
> index out of range" error.
> 
> Am I overlooking something?

    	It's not legal to assign to an element that doesn't already exist 
in the list.  Your list has no elements, so it's not legal to assign to 
any index.  What you want is:

for r in row:
    	header.append(r[0])

-- 
--OKB (not okblacke)
"Do not follow where the path may lead.  Go, instead, where there is
no path, and leave a trail."
	--author unknown