List slice assignment and custom sequences

[Erik Max Francis]

Ronald Oussoren wrote:

> I traced this to the implementation of this feature in type 'list': It
> requires that the new version of the slice is also a 'list':
> 
>         l = [ 1, 2, 3, 4]
>         l[1:3] = range(10)      # works fine
>         l[1:3] = xrange(10) # raises TypeError
> 
> Why must the RHS side of 'l[1:3] = expr()' be an instance of 'list'?

Well, you want to splice one list into another.  Both have to be lists. 
To convert any sequence S to an actual list, use the list builtin:

	list(S)

So you'd just write your problem code as

	l[1:3] = list(xrange(10))

Although in this case, needless to say, range(10) would make a great
deaal more sense.

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