Python embedding question: how to expose a new "builtin"?

[Rodrigo B. de Oliveira]

> > 
> > After the code "dir(type(application))" executes everything works as
> > expected (application is correctly installed and I can call its
> > methods and access its properties).
> > 
> > What could be possibly causing this behavior?
> 
> Never saw it happen before.  Maybe you're not calling PyType_Ready, or
> something of that ilk...?
> 

Uops... That's what sleepless nights and no caffeine do to you :-) My
init function had the following statements:
<snip>
if (PyType_Ready(&isapy_ExtensionControlBlockType) &&
    PyType_Ready(&isapy_ApplicationType))
{
    return;
}
</snip>

The damage a short circuiting operation can cause, eh?

Thanks very much for the help!
Rodrigo