How does Python handle probing to see if a file already exists?

[Leazen]

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Oh, access is in the os module.

Leazen


Leazen wrote:
> The other answers are probably better but if you like the C way you
can use:
>
> access(path, mode)
> Check read/write/execute permissions for this process or existence of
> file path. mode should be F_OK to test the existence of path, or it can
> be the inclusive OR of one or more of R_OK, W_OK, and X_OK to test
> permissions. Return 1 if access is allowed, 0 if not. See the Unix man
> page access(2) for more information. Availability: Unix, Windows.
>
> F_OK
> Value to pass as the mode parameter of access() to test the existence of
> path.
>
> Just like you could in C.
>
> Leazen
>
>
>
> Christopher R. Culver wrote:
>
>>Hello all,
>>
>>I've just begun learning Python after already getting pretty proficient in
>>C. However, I'm having a problem with a simple copying program. Ideally,
>>the program would check to see if the destination already exists and
>>prompt the user. In this this would be as easy as saying:
>>
>>probe_destination = fopen(/usr/bin/foo, 'r')
>>if (probe_destination)
>>{
>>some code here;
>>}
>>
>>However, translating that directly into Python doesn't work because if
>>Python can't find a file to open, it doesn't just return 0, it gives an
>>error and exits. How can I write this functionality in Python so that it
>>returns 0 and continues, or does Python have a totally different way of
>>handling this problem than C?
>>
>>Christopher Culver
>>
>>
>
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