matching one time through a loop

[Justin Dubs]

You can do it just as you would in perl.  The python equivalent of "last" is
"break", more or less.

>>> for i in range(10):
...     print i
...     if (i == 2):
...         break
0
1
2

Hope this helps,

Justin Dubs

"Corey G." <ctgaff at attbi.com> wrote in message
news:mailman.1022721348.30810.python-list at python.org...
> I have a script that parses some email from a Maildir directory
> and I am looking for the number 550.  I want to stop searching once
> the first occurrence is found in order to save time and be efficient.
> This sort of thing can be done in Perl using the "last" statement.
> I achieved my goal by using a counter but it seems terribly inefficient.
> Any ideas?
>
>
> #!/usr/local/bin/python
>
> import re
> import glob
>
> tglob=glob.glob('/home/pmail/Maildir/test3/*')
>
> for i in tglob:
>         count=0
>         file=open(i, 'r')
>         contents = file.readlines()
>
>         for sepem in contents:
>                 tm=re.compile(" 550 ")
>                 match=tm.search(sepem)
>                 if match:
>                         if count == 0:
>                                 count+=1
>                                 print match.group(), i
>
> --
> Best Regards,
> Corey
>
>