Iterating over the cells of an array?

[Alex Martelli]

Fernando Pérez wrote:
        ...
> ravel is I believe a copy operation, much more expensive than a call to

Chacking isn't all that expensive, is it?

>>> x=Numeric.array([range(n,n+4) for n in range(3)])
>>> x
array([[0, 1, 2, 3],
       [1, 2, 3, 4],
       [2, 3, 4, 5]])
>>> f=Numeric.ravel(x)
>>> f
array([0, 1, 2, 3, 1, 2, 3, 4, 2, 3, 4, 5])
>>> x[1,1]=111
>>> x
array([[  0,   1,   2,   3],
       [  1, 111,   3,   4],
       [  2,   3,   4,   5]])
>>> f
array([  0,   1,   2,   3,   1, 111,   3,   4,   2,   3,   4,   5])
>>>


Alex