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[Michael Chermside]

> If you mean requirement to say def meth(something, arg) instead of def
>> meth(arg), compiler does not necesarily know when compiling whether
>> function will be used as method or not.  (Methods can be defined
>> outside of class statement and assigned as method later.)
> 
> Yes, this is what I meant. How does this work though, when assigning a
> method to a class? I mean, let's say that you have a method taking two
> arguments, concatenate (x, y). When assigning this method to a class,
> will that mean that the first argument is always replaced by the class
> instance, so I'd have to call it like this: aclass.concatenate (y), and
> the first argument, x, will always correspond to aclass?

Yes.



Python 2.2c1 (#27, Dec 14 2001, 13:15:16) [MSC 32 bit (Intel)] on win32
Type "copyright", "credits" or "license" for more information.
IDLE 0.8 -- press F1 for help
 >>> class MyClass:    # CREATE A CLASS
	pass

 >>> def concatenate(x, y):     # CREATE A FUNCTION
	print 'concatenating %s and %s' % (x,y)
	return [x, y]

 >>> MyClass.concatenate = concatenate   # MAKE THE FUNC A METHOD!
 >>> myInstance = MyClass()          # NEED AN INSTANCE
 >>> myInstance.concatenate(7)      # CALL METHOD ON THE INSTANCE
concatenating <__main__.MyClass instance at 0x009557A8> and 7
[<__main__.MyClass instance at 0x009557A8>, 7]