Default arg for dict() (was Re: Sorting distionary by value)

[Emile van Sebille]

John Machin
> Python *could* be made like that with the explict dict() constructor
> ... something like:
> 
> freq = dict(default=0)
> ...
> freq[word] += 1

Or you could subclass with something like:

>>> class ddict(dict):
...     def __getitem__(self, ky):
...             return self.setdefault(ky, self.default)
...     def __init__(self, default=None):
...             self.default = default
...
>>> d = ddict(0)
>>> d['a']+=1
>>> d['a']
1

-- 

Emile van Sebille
emile at fenx.com

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