Newbie regex question.

[Omri Schwarz]

"Sean 'Shaleh' Perry" <shalehperry at attbi.com> writes:

> On 13-Mar-2002 Omri Schwarz wrote:
> > 
> > I have a regex = re.compile('yadda (widget1) (widget2) yadda')
> > and want to search a string I know to have multiple 
> > instances of this regex. I'm a tad confused by
> > the RE Howto, so I'd like to ask, how do I properly 
> > get a for loop to access the widget1 and widget2 
> > strings of each instance?
> > 
> > for instance in regex.search(string).groups() 
> > seems to be the right thing, but isn't working.
> > 
> 
> >>> import re
> >>> s= 'yadda widget1 widget2 yadda'
> >>> regex = re.compile('yadda (widget1) (widget2) yadda')
> >>> for match in regex.search(s).groups(): print match
> ... 
> widget1
> widget2
> 
> This works here.  Although I would strongly caution you to do:
> 
> re_match = regex.search(s)
> if re_match != None ......
> 
> just in case the regex fails.

What I was trying to get was 
widget1 of instance 1
widget2 of instance 1
widget1 of instance 2
widget2 of instance 2
...



> 

-- 
Omri Schwarz --- ocscwar at mit.edu ('h' before war) 
Timeless wisdom of biomedical engineering: "Noise is principally
due to the presence of the patient." -- R.F. Farr