squared functions--most Pythonic way?

[Janto Dreijer]

I think that's a typo:
>>> print AddNumbers(5)
5

How about:
reduce(lambda a,b: a(b), range(10), addNumbers)
or
reduce(apply, [[i] for i in range(10)], addNumbers)

"Opus" <opus at value.net> wrote in message news:<mailman.1025423271.21617.python-list at python.org>...
> Shouldn't addNumbers(5) equate to 5?  In other words, it should evaluate that 
> as addNumbers(5)(0) or is that addNumbers(0)(5)?
> 
> How would you send a list of numbers (or objects that represent numbers) to 
> this?
> 
> On 30 Jun 2002 at 19:24, greg wrote:
> 
> > Janto Dreijer wrote:
> > > 
> > > def addNumbers(k):
> > >     def f(x):
> > >         a = addNumbers(x + k)
> > >         a.val = x+k
> > >         return a
> > >     return f
> > > 
> > > >>> addNumbers(9)(5)(2)(4)(6).val
> > > 26
> > > 
> > > Now if only I could figure out how to use __repr__() so I don't 
> > > need that ".val". It also fails when passed only one number. i.e
> > > addNumbers(5). Help?
> > 
> > class AddNumbers:
> > 
> >   def __init__(self, x):
> >     self.val = x
> > 
> >   def __call__(self, k):
> >     return AddNumbers(self.val + k)
> > 	
> >   def __repr__(self):
> >     return repr(self.val)
> > 
> > addNumbers = AddNumbers(0)
> > 
> > >>> print addNumbers(9)(5)(2)(4)(6)
>  26
> > >>> print addNumbers(5)
> > 0
> >