I feel stoopid ... this code is to verbose
John La Rooy
larooy at xtar.co.nz
Sun Jun 16 02:57:01 EDT 2002
On Fri, 14 Jun 2002 18:19:29 +0200
Max M <maxm at mxm.dk> wrote:
> Hmm ... I am working on a problem. In Danish we have a number format
> that looks like:
>
> 42.000.000,00 which is 42 millions
>
> So I need to insert dot's at every three character from end of the
> string for the integer value of the number.
>
> Let's discard decimal points and just focus on the meat. I have written
> a funcion which works::
>
> def stringSlicer(string, chunkSize=3):
> chunkList = []
> reverseString = list(string)
> reverseString.reverse()
> for i in range(0, len(string), chunkSize):
> chunk = reverseString[i:i+chunkSize]
> chunk.reverse()
> chunk = ''.join(chunk)
> chunkList.append(chunk)
> chunkList.reverse()
> return '.'.join(chunkList)
>
>
> print stringSlicer('42000000')
>
> >>> 40.000.000
>
> I just find that it's a lot of code for such a little function an it
> annoys my sense of aestetics. I have tried a lot of different approaches
> including using zip on a list like ['','','.'], and other weird stuff :-)
>
> I just cannot seem to find the nice 3-liner I expected from the
> beginning. Has anybody got a better solution ? I thought somebody might
> find it a fun exercise. Well I have...
>
>
> regards Max M
>
As other people have pointed out already, the locale module is the way to go
but some people do find it a fun exercise too ;o)
(this breaks if you have more than 3 digits after the decimal point. what's
supposed to happen then anyway?)
import re
def StringSlicer(s):
return re.sub("\\B(\d{3})(?=(\d{3})*(,\d*)?$)",".\\1",s.replace(".",","))
John
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