arguments to functions
Uwe Mayer
merkosh at hadiko.de
Sun Jun 30 21:52:10 EDT 2002
hi,
I wanted to pass one named and a collection of unnamed (an arbitrary
number) to a function:
def test(expected=None, *misc):
print(expected)
print(misc)
Now, unluckyly 'test' interprets the first unnamed parameter to test as
the value for 'expected':
test(5, expected=10)
TypeError: test() got multiple values for keyword argument 'expected'
on the other side any keyword arguments must follow non-keyword
arguments:
test(expected=5, 10)
SyntaxError: non-keyword arg after keyword arg
Which is a pitty, because I think this version is clear.
Is that *it*, or am I doing something wrong here?
Thanks
Uwe
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