UnboundLocalError: local variable part 2

[Daniel]

That last example was a bit too contrived... instead of blah='abc',
blah is actually a list and i'm appending and popping elements so
func1 actually truly does affect the global blah.  So a better example
of the logic is:

def func1():
   blah.pop()

def func2():
   print blah
   blah.pop()

def main():
   func1()
   try:
      func2()
   except:
      pass
   print blah

blah=[1,2,3]
main()

except instead of:
[1, 2]
[1]

it's getting:
[1, 2]
(trap the UnboundLocalError)
[1, 2]
 
I've looked through and cannot find anything that vi might have put in
that is throwing the python interpreter off.

Any thoughts on what might cause this behavior?
Thanks,
Daniel