[Newbie] How to output dictionary sorted on content (not keys)

[Eric Brunel]

Achim Domma wrote:
> not tested, but something like this should work:
> 
> //    can this be done with lambda ???
> def myComp(a,b): return cmp(a[1],b[1])
> tmpList = yourDict.items()
> tmpList.sort(myComp)
> 
> for name,count in tmpList: print name,count

Here is an almost one-liner version:

l = [(i[1], i[0]) for i in yourDict.items()]
l.sort()

or:

l = zip(yourDict.values(), yourDict.keys())
l.sort()

I don't which one of these two or Achim's one is the most efficient.

HTH
-- 
- Eric Brunel <eric.brunel at pragmadev.com> -
PragmaDev : Real Time Software Development Tools - http://www.pragmadev.com