obj2 = ojb1 = range(len(somelist))
Paul Rubin
phr-n2002a at nightsong.com
Thu Jan 31 18:17:11 EST 2002
David Bear <iddwb at moroni.pp.asu.edu> writes:
> I wanted to create 2 distinct lists that were derived from range
> function. rather that doing
>
> obj1 = range(len(somelist))
> obj2 = range(len(somelist))
>
> I wanted to do
>
> obj2 = ojb1 = range(len(somelist))
>
> Yet, both names point to the same object -- they're not two objects.
>
> Is there some other syntax that I could use to avoid having to call
> range(len(list)) twice and still create two objects?
obj1 = range(len(somelist))
obj2 = obj1[:]
I don't see why that's any better though.
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