filter() and booleanness

[Oleg Broytmann]

Hi!

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> Hi there, the following two calls will both print ('hi', 'there') due
> to None being substituted for `identity function' (as the docs say):
> 
> print filter(None, ('hi', None, 0, 'there'))
> print filter(lambda x: x, ('hi', None, 0, 'there'))
> 
> Then I thought I'd clamp the x to [0..1] but things like x != 0 missed
> None and x != None missed 0. :) Now I have lambda x: not not x, is it
> bulletproof? (it seems to work).

   But what do you want to achieve?

Oleg.
-- 
     Oleg Broytmann            http://phd.pp.ru/            phd at phd.pp.ru
           Programmers don't die, they just GOSUB without RETURN.