getting "this" module's path

[Neal Norwitz]

"Clark C . Evans" wrote:
> 
> How do I get the path name for a module (in particular,
> the module that is currently executing?).

I believe what you are asking for is:

	import sys
	this_module = sys.modules[__name__]
	print this_module.__file__

Although when I tried this when __name__ == '__main__' and 
it didn't seem to work.  It should for other modules imported.

Neal