Soundcard shenanigans

[Tom Loredo]

Anton Vredegoor wrote:
> 
> Maybe a von
> Neumann correction would be adequate here. It consists of converting a
> bit pair [0,1] into an output 1, converting [1,0] into an output 0,
> and outputting nothing for [0,0] or [1,1] .

Provided the input is not entirely 1's or 0's, this provides an
output that will have 0's and 1's with equal long-run frequency,
but guarantees no other useful properties of "randomness."

-Tom Loredo