Fun with lambda and map

[gbreed at cix.compulink.co.uk]

Gerson Kurz wrote:

> If you're in a masochistic mood, you can write this in one line:
> 
> fac = lambda n:map(lambda x:(map(lambda a:a and 1,[x[0]()])[0] and
> x[1]()) or x[2](x[3]),[[lambda:not n,lambda:n==n,lambda
> n:fac(n-1)*n,n]])[0]

If you're allowing booleans and subtraction, how about

fac = lambda x: not x or x*fac(x-1)

?


                Graham

    (<http://www.microtonal.co.uk/>)