confusion regarding os.path.walk()

[Ron Johnson]

Hello,

In the visit callout function, it looks as though after the top level
is processed, os.path.isfile() and os.path.isdir() both return 0 when 
passed elements from the names parameter.

Am I doing something wrong?

Here is an examle:
me at rebel:~/test$ python
Python 2.2 (#1, Jan  8 2002, 01:13:32) 
[GCC 2.95.4 20011006 (Debian prerelease)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> 
me at rebel:~/test$ cat test.py
import os.path, string
def test(arg, dirname, names):
    print arg
    print dirname
    names.sort()
    for n in names:
        print n,
        if os.path.isdir(n): 
            print ' is a DIR'
        elif os.path.isfile(n):
            print ' is a FILE'
        else:
            print ' is UNKNOWN'
    print '================================'
os.path.walk('.', test, None)
me at rebel:~/test$ python test.py
None
.
bar  is a DIR
foo  is a DIR
snafu  is a DIR
test.py  is a FILE
================================
None
./bar
================================
None
./foo
snaggle  is UNKNOWN
swizzle  is UNKNOWN
================================
None
./foo/swizzle
================================
None
./snafu
================================

TIA,
Ron
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| Ron Johnson, Jr.        Home: ron.l.johnson at cox.net        |
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