How do you conver output of "popen('ls')" to a list?
husam
husam at macrozon.net
Wed Feb 20 07:09:26 EST 2002
Neil Schemenauer wrote:
> I'm a bit late coming in on this thread but what's wrong with:
>
> os.listdir('.')
>
> It's more portable and faster.
>
> Neil
os.listdir('.') gets you all the files in the '.' dircetory. This want
work if i want to process some selected files. In contrast to this,
"os.popen() allows you to pass arguments like "ls *txt" to retrieve only
*.txt files.
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