overload operator()?

[Andrew Dalke]

Chris Liechti wrote:
> that would be __call__ but some people say that overloading operators leads 
> to confusing code...

I have a regexp engine with ideas based on Greg Ewing's
Plex.  It lets you do regexp-style parsing of complex data files.
It builds up the regexp from parts.  This makes it easier to
construct valid regexps.  Suppose you have

from Martel import *
s = Re("a*b*")
t = Re("c*")


Many would say that

u = s.add(t)
   -or-
u = add(s, t)

is more confusing than

u = s + t

Given that the result, u, is equivalent to

   Re("a*b*c*")

Ie, exactly like adding two strings together.

					Andrew
					dalke at dalkescientific.com