How to store the reference of a dictionary element ?

[Alfredo P. Ricafort]

Not quite, but I can live with it if there are no more simple solution.

I am really planning to implement the 'values' as list.  They are
actually attributes of a record. But my problem with this code is if I
mistakenly do this:

  a['2']=[22] 

instead of 

  a['2'][0]=22

then the link would be broken and I would end up with an orphan child in
my linked list. Currently, the number of attributes are not that many so
I can still afford to subscript each element during assignment.


> Try this:
> 
> >>> a = {'1':[1], '2':[2]}
> >>> 
> >>> b = {}
> >>> b['2']=a['2']
> >>> a['2'][0]= 22
> >>> b
> {'2': [22]}
> 
> can that do what you need?
> 
> Cheers,
> Terry
> 
> --
> Terry Hancock ( hancock at anansispaceworks.com )
> Anansi Spaceworks  http://www.anansispaceworks.com
> 
> "Some things are too important to be taken seriously"