confusion with __add__ and __radd__

[Terry Hancock]

Walter Moreira wrote:

> Hello. I'm confused about the behavior of the 'reverse' methods
> __radd__, __rmul__, etc, and Google didn't help me.
[...]
>     
> Why isn't the __radd__ method called, since __add__ returns
> 'NotImplemented'? If 'Foo' is a classic class it works ok.  Am I
> overlooking something obvious?

AFAIK, __radd__ is being phased out, starting in 2.2 (the whole series of 
"reversed" operators). I don't really understand the new syntax (not sure I 
fully understood the old one), but this would explain why "newstyle" 
classes wouldn't have implemented it.  My guess is that the newer classes 
make it unnecessary in some way. You'll want to look at the Python 2.2 
release notes I think.

Cheers,
Terry

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