[PYTHON URLLIB2] HELP ME HELP ME HELP ME (Italian boy)

[Wojtek Walczak]

Dnia Thu, 05 Dec 2002 16:57:14 GMT, PigioŽ napisał(a):
> My problem is this: I would like modify urllib2 exception HTTPError to
> permit it returns more attributes that I can use to read web page souce
> code.
> I have understood that I must add args attribute such tuple of  return
> element (but I don't have understood the reason) but, what can I do to add
> this attribute if  HTTPError class doesn't declare its attributes at
> beginning?
I'm not absolutely sure what you're trying to achieve, but I think
you want to change that(i.e.):

"HTTP Error 404: Not Found"

generated by this code:
---
import urllib2

try:
   a = urllib2.urlopen("http://www.python.org/blah.blah")
except urllib2.HTTPError, msg:
   print "%s" % (msg)
---

into something more complicated, like this:

"HTTP error: <http://www.python.org/blah.blah>: Not Found (404)."

If I'm right, take a look at this code:

----
import urllib2

class h(urllib2.HTTPError):
   def __init__(self, url, code, msg, hdrs, fp):
      self.url = url
      self.code = code
      self.msg = msg
      self.hdrs = hdrs
      self.fp = fp

   def __str__(self):
      return 'HTTP error: <%s>: %s (%s).' % (self.url, self.msg, self.code)

urllib2.HTTPError = h

try:
   a = urllib2.urlopen("http://www.python.org/blah.blah")
except h, msg:
   print "%s" % (msg)
----

HTH.

ps. I'm not a master of subclassing, so, I think language purists will
    improve correctness of that code above ;]

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