question about generators

[Duncan Booth]

Andrew Koenig <ark at research.att.com> wrote in 
news:yu994rdo1hvd.fsf at europa.research.att.com:

> Delaney> However, in neither case would you be able to use
> 
> Delaney>     yield every <seq>
> 
>     def product(s, *sets):
>         if not sets:
>             yield every [(x,) for x in s]
>         else:
>             subproduct = list(product(*sets))
>                 yield every [(x,) + t for x in s for t in subproduct]
> 
> I should think that would work as long as "yield every" takes an
> iterable rather than just a generator.

But this defeats the whole point of using a generator as it builds a 
complete list of results every time.

-- 
Duncan Booth                                             duncan at rcp.co.uk
int month(char *p){return(124864/((p[0]+p[1]-p[2]&0x1f)+1)%12)["\5\x8\3"
"\6\7\xb\1\x9\xa\2\0\4"];} // Who said my code was obscure?