Does Python need a '>>>' operator?

[David Eppstein]

In article <m38z7pmq4p.fsf at mira.informatik.hu-berlin.de>,
 martin at v.loewis.de (Martin v. Loewis) wrote:

> Indeed, if you write
> 
> >>> 0x40000000L<<1
> 2147483648L
> 
> it works the way you expect it to work. Please see
> 
> http://www.python.org/peps/pep-0237.html
> 
> Python has currently completed phase A of the PEP, meaning that
> operations that previously raised an OverflowError now return a long;
> nothing else has changed.
> 
> Notice that your example is the historic meaning of shift; in phase
> B.1, it will change to the arithmetic meaning (multiplication with
> 2). Since this is a semantic change, you'll get a warning if you make
> use of a short int shift that loses a bit.

Thanks.  I notice the PEP doesn't actually say anything about signs, 
though, it just talks about losing bits, so I hope this example is 
covered.

Is there some way of getting the arithmetic meaning now, without a 
warning, using a __future__ import?

-- 
David Eppstein       UC Irvine Dept. of Information & Computer Science
eppstein at ics.uci.edu http://www.ics.uci.edu/~eppstein/