Does Python need an 'xor' operator?

[Boris Borcic]

Tim Peters wrote:

> I doubt that a new "xor" operator will ever get in (compelling use cases are
> conspicuous by absence), but anyone pushing for it had better push for a new
> "eqv" operator too (that is, if you're going to claim that it's ugly that
> x^y may not return one of its argument, surely it's just as ugly that the
> same holds for x==y).


Indeed, x == y should behave like (x == y) and (x or not y) !

Boris
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